Molecular mass of CH3 OH =

32g/mol

Explanation:

When dealing with a compound, the molar mass is the gram - formula mass or gram moleclular weight. This is determined by the addition of its component atomic masses.

For CH₃OH;

Atomic mass of C = 12g/mol , H  = 1g/mol, O  = 16g/mol

 So,

     Molecular mass  = 12 + 3(1)  + 16 + 1  = 32g/mol

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm