If you add 90 mL of 0.15M stock solution, to 10 mL of water, what is the new concentration?

0,15 moles of NaOHin1000ml

x moles of NaOHin100ml

x = 0,015 moles of NaOH

final volume = 150ml

0,015 moles of NaOH---in150ml

x moles of NaOHin1000ml

x = 0,1 moles of NaOH

 0,1mol/dm³  (molarity)

while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.