Write yes or no if any of the following reactions could be written as net ionic equations. a. CH4 (g) + 2 O2 (g) = CO2 (g) + 2 H2 O(g)
b. Cu(s) + 2 AgNO3 (aq) = 2 Ag(s) + Cu(NO3 )2 (aq)
c. MgCl2 (aq) + 2 KOH(aq) = Mg(OH)2 (s) + 2 KCl(aq)
d. CaCO3 (s) + 2 HCl(aq) = CaCl2 (aq) + CO2 (g) + H2 O(l)

Well you can immediately rule out a and d because if a metal were to lose or gain protons, then it would become a different element all together. the answer here is b because the positive symbol with a number refers to how many electrons the metal can give away to become stable.

For apex it is hydroxyl

Answer: =6.19lexplanation: by ideal gas equation we know,hope this : )

Answer: 1s²  2s²  2p⁶explanation: from the periodic table, we can note that the neutral fluorine  has 9 electrons (symbol is shown in the attached image)therefore, the configuration of neutral fluorine  is: 1s²  2s²  2p⁵now, f⁻  means that the neutral fluorine  gained one extra electron. this means that f⁻  has 10 electrons.the extra electron will occupy the 2p level to make it complete.the configuration now  is: 1s²  2s²  2p⁶comparing between both f and f⁻, we can note that f⁻  has now complete orbitals which means that it is more stable than f based on lewis postulatehope this : )