Calculate the molarity of 32.9 g32.9 g of MgS MgS in 971 mL 971 mL of solution.

0.60 M

Explanation:

Given data:

Mass of MgS = 32.9 g

Volume of solution = 971 mL (0.971 L)

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of MgS:

Number of moles = mass/molar mass

Number of moles = 32.9 g/ 56.38 g/mol

Number of moles = 0.58 mol

Molarity of solution:

M = 0.58 mol/ 0.971L

M = 0.60 M

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally