Write the balanced equation for the reaction that occurs when Iron (III) nitrate is mixed with magnesium oxide forming iron(III) oxide and magnesium nitrate

2Fe(NO₃)₃  +  3MgO  →  Fe₂O₃  + 3Mg(NO₃)₂

Explanation:

Given chemical species:

  Reactants:  Iron(III) nitrate

                      Magnesium oxide

 Products:  Iron (III) oxide

                   Magnesium nitrate

The chemical symbols:

   Fe(NO₃)₃  +  MgO  →  Fe₂O₃  + Mg(NO₃)₂

The reaction of this type is called a double displacement reaction.

 Now let us ensure that it is balanced;

         aFe(NO₃)₃  +  bMgO  →  cFe₂O₃  + dMg(NO₃)₂

Conserving Fe;

           a  = 2c

Conserving N;

           3a  = 2d

 Conserving O

            9a  + b  = 3c + 6d

 Conserving Mg

           b  = d

let a  = 1, c  = , d = , b =  

 multiply through by 2;

     a = 2, c  = 1, d  = 3 and b  = 3

     2Fe(NO₃)₃  +  3MgO  →  Fe₂O₃  + 3Mg(NO₃)₂

explanation:

i think option no d is the correct answer

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j