How many milliliters of a 0.266 M CsNO3 solution are required to make 150.0 mL of 0.075 M CsNO3 solution

The required milliliters of CsNO3 in solution 1 = 42.29 mL

Explanation:

Given that:

The molarity of CsNO3 in solution 1 M₁= 0.266 M

The Volume of CsNO3 in solution 1 V₁  =   ???

The Volume of CsNO3 in solution 2 V₂ = 150.0 mL

The molarity of CsNO3 in solution 2 M₂= 0.075 M

By the application of the titrimetric concept:

M₁V₁ = M₂V₂

We have;

0.266 M ×  V₁  = 0.075 M × 150.0 mL

V₁  = ( 0.075 M × 150.0 mL ) / 0.266 M

V₁  = (11.25 / 0.266 ) mL

V₁  = 42.29 mL

i think so it’s will be b yes i believe its

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates