Assuming that Coca-Cola has the same specific heat as water [4.18 J/(g°C)]. Calculate the amount of heat in kilojoules transferred when one can (about 350 gg) is cooled from 21°C to 8°C.

Heat transferred in the process is 19019J

Explanation:

Using the equation:

Q = S×m×ΔT

We can solve the energy transferred in the process, Q, where:

S is specific heat = 4.18J /(g°C)

m is mass = 350g

ΔT is change in temperature (21°C - 8°C = 13°C)

Q = 4.18J/(g°C)×350g×13°C

Q = 19019J

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i think that the answer is c