When magnesium ribbon reacts with steam, a solid called magnesium oxide and hydrogen gas are formed. Which of the following is the correct
word equation?
O magnesium + hydrogen -> magnesium + water
magnesium + water -> magnesium oxide + hydrogen
O magnesium + water -> magnesium + hydrogen
O magnesium + magnesium oxide -> hydrogen + water

magnesium + water == magnesium oxide + hydrogen

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

the answer is   c.) 1575 j.

explanation: