A 1.50 mol sample of He occupies a volume of 2.50 L at a pressure of 14.7 atm. What will be the pressure of a 1.50 mol sample of H2 gas under the same conditions? a 7.33atm b 14.7atm c 29.4 atm d 1.00 atm

el n = M/m. El nº de moles = m/M

Se utiliza la fórmula general de los gases: P*V = n*R*T

P = 760/760 = 1 atm

V = 0,5 L

n = masa de Cl2/masa molecular = masa de Cl2/70

R = 0,082

T = 273 + 20º C = 293 K

1*0,5 = masa de Cl2/70*0,082*293

0,5/0,082*293 = masa de Cl2/70

0,0208 = masa de Cl2/70

masa de Cl2 = 70*0,0208 = 1,46 g

epilacion:

Suerte

explanation:

0.07 g/cm³

1.37 g/cm³