A cube of iron and a cube of wood, each having a volume of V = 3.25 10-4 m3, are each placed in a large beaker of water. The density of the wood is rhowood = 3.73 102 kg/m3 and the density of the iron is rhoiron = 7.86 103 kg/m3. Calculate the buoyant force on each. (The cube of wood is allowed to float at the surface.)

anor277

Nov 17, 2017

Well, by definition,

Molarity

≡

Moles of solute

Volume of solution

Explanation:

And thus...

moles of solute

=

molarity

×

volume

We use a molar quantity of

80.3

⋅

g

174.01

⋅

g

⋅

m

o

l

−

1

=

0.461

⋅

m

o

l

with respect to

potassium sulfate

And thus

volume

=

moles of solute

molarity

80.3

⋅

g

174.01

⋅

g

⋅

m

o

l

−

1

3.12

⋅

m

o

l

⋅

L

−

1

=

0.148

⋅

L

.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

the increase of protons   hope this