What is the frequency of a photon with an energy of 3.38 x 10-19 J?

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E =

h =

f = ?

Energy of Photon is given by,

                                   E = hf

Rearrange the equation,

                                    f =

where,

           E = energy

           h = planck's constant

           f = frequency

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Substitute the variable in the equation,

                                 f =

Simplify the equation,

                                  f = 5.10 x 10^14 Hz          

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answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.