A reaction has a theoretical yield of 124.3 g SF6, but only 113.7 g SF6 are obtained in the lab, what is the percent yield of SF6 for this reaction?

Percent yield = 91%

Explanation:

Given data:

Theoretical yield of SF₆ = 124.3 G

Actual yield of SF₆ = 113.7 g

Percent yield of SF₆ = ?

Solution:

Formula:

Percent yield = (actual yield / theoretical yield)× 100

By putting values,

Percent yield = (113.7 g/ 124.3 g) × 100

Percent yield = 0.91 × 100

Percent yield = 91%

the correct answer to this question is 2