Ammonia gas(NH3) and oxygen(O2) gas react to form nitrogen gas and water vapor. Suppose you have 2.0 mol of and 13.0 mol of O2 in a reactor. Calculate the largest amount of that could be produced. Round your answer to the nearest .

Explanation:

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In this case, for the described reaction we have:

Which means there is 2:3/2 mole ratio between ammonia and oxygen and we use it to compute the consumed moles of ammonia by 13.0 moles of oxygen as shown below:

However, since just 2.0 mol of ammonia is available, we infer it is the limiting reactant and the maximum amount of both nitrogen and water that can be produced is computed below:

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