Q 1. Element M is a metal that forms compounds of the type MX2, MX3, and MX4, where X is a Chlorine (Cl). I) What is the expected trend in the ionic radius of M in these compounds?
II) Arrange these compounds in order of decreasing ionic radius of M.

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See explanation

Explanation:

The ionic radius of metal M decreases as the charge on the metal M increases. The ionic radius is generally defined as the distance between the nucleus and the outermost electron of the ion. Hence, ionic radius becomes much lesser as the magnitude of the positive charge increases.

It is obvious  from the various formulae of metal chlorides in the question that the metal forms cations M^2+, M^3+ and M^4+ respectively. The order of decreasing ionic radius of the compounds is;

MX2 > MX3 > MX4

answerto predict;

5 structural isomers

the isomers are:

n-exane :   ch3ch2ch2ch2ch2ch3

2-methylpentane :   ch3ch(ch3)ch2ch2ch3

3-methylpentane :   ch3ch2ch(ch3)ch2ch3

2,3-dimethylbutane :   (ch3)2chch(ch3)2

2,2-dimethylbutane :   (ch3)3cch2ch3