1. A gas at 116 kPa and 303 K fills a container at 2.0 x 105 L. If the temperature changes to 293 K, What is the new pressure?

P₂ = 112.17 KPa

Explanation:

Given data:

Initial pressure = 116 KPa

Initial temperature = 303 K

Final temperature = 293 L

Final pressure = ?

Volume=  constant

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

116 KPa / 303 K = P₂/293 K

P₂ = 116 KPa × 293 K  / 303 K

P₂ = 33988 KPa. K / 303 K

P₂ = 112.17 KPa

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

because of all the things that happen around the us, many people get into arguments which sadly could get physical, but we should actually make a change for that.