How much heat is needed to raise a 0.060 kg piece of granite from 82°C to 212 °C. (The specific heat capacity of granite is 0.790

There are required 6162J to raise the temperature of the piece of granite from 82°C to 212°C

Explanation:

By using the equation:

Q = m×C×ΔT

Where Q is heat in J, our incognite

m is mass of the substance, 0.0600kg = 60.0g

C is specific heat, 0.790J/g°C

And ΔT is change in temperature, 212°C - 82°C = 130°C

Replacing:

Q = m×C×ΔT

Q = 60.0g×0.790J/g°C×130°C

Q = 6162J

it should be p1 v1 = p2 v2

wher is the rest of the question