What volume (mL) of 0.2173M NaOH is required to titrate 50.00mL of 0.2980M HCI?

68.6 mL

Explanation:

We need to use the equation M1V1=M2V2. Molarity's units are in L so we need to convert the 50 ml into L (divide by 1000).

.05(.298)=(x)(.2173)

x = .068 L

to convert to mL we multiply by 1000

.068*1000=68.6 mL

c. 75.7

i think that is the right

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