An aqueous solution of potassium hydroxide is standardized by titration with a 0.187 M solution of nitric acid. If 22.7 mL of base are required to neutralize 29.4 mL of the acid, what is the molarity of the potassium hydroxide solution?

Explanation:

29.4 mL of nitric acid having molarity of .187M reacts with 22.7 mL of potassium hydroxide .

moles contained in nitric acid solution

= .0294 x .187 moles

= 5.5 x 10⁻³ moles

This must have been reacted with same amount of moles of base

moles of sodium hydroxide in 22.7 mL of solution = 5.5 x 10⁻³ moles

molarity of base solution = 5.5 x 10⁻³ / 22.7 x 10⁻³

= .24 M .

b. is the answer hoped i        

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.