What is the empirical formula of a molecule containing 24% carbon (C), 6% hydrogen (H), and 70% chlorine (CI)?
O A. CH3C1
B. C2H6Cl2
C. C24H6C170
O D. CHCI
SUBMIT

Empirical formula is CH₃Cl.

Explanation:

Given data:

Percentage of hydrogen = 6%

Percentage of carbon = 24%

Percentage of chlorine= 70%

Empirical formula = ?

Solution:

Number of gram atoms of H = 6/ 1 = 6

Number of gram atoms of C = 24 /12=  2

Number of gram atoms of Cl = 70/ 35.45 = 2

Atomic ratio:

            C                      :      H            :         Cl

           2/2                    :     6/2           :       2/2

            1                       :        3          :        1

C : H : Cl = 1 : 3 : 1

Empirical formula is CH₃Cl.

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.

the answer is 0.8m.

by: nicholas