Which of the following observations would be the expected indication that a reaction has taken place when a solution of cesium sulfate is mixed with strontium perchlorate. Bubbling
Formation of percipitate
Formation of soluble salts
Formation of a gas

Formation of precipitate

Formation of soluble salts

Explanation:

Let's consider the molecular equation that takes place when an aqueous solution of cesium sulfate is mixed with an aqueous solution strontium perchlorate.

Cs₂SO₄(aq) + Sr(ClO₄)₂(aq) ⇒ 2 CsClO₄(aq) + SrSO₄(s)

According to the solubility rules:

For a double displacement reaction to occur, at least one of the products must be insoluble or volatile.

It's b) Formation of a precipitate

Explanation:

I took the quiz and got it right.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o