The following image shows the Atomic level of an element. In the image, which of the following processes is NOT taking place as the element becomes stable. *
152 25+ 2p 35
152252 2p on ~ (Nel
le-
Na
+
Nat"
Tose
Iyolence election
8 valence electrons
O The loss of an electron Anveils an octet at the 2nd energy level to make it stable
The loss of an electron allows the element to take on a noble gas electron
configuration
Na is sodium is a metal and loses 1 e-
O The cation will use a type Ii naming system
O Na is neutral, loses 1 e- and then becomes a positive charged ion Na+

D. The cation will use a type II naming system

Explanation:

As the element becomes stable, Option D is NOT taking place. That means that as the element becomes stable, the cation will NOT use a type II naming system. This is because in Type II binary compounds, the metal is not found in either Group 1 or Group 2 on the periodic table. It is as a result of this that the cation will not use a type II naming system.

Group 1 and Group 2 elements make use of type I naming system because in Type I binary compounds, the metal is present.

Option D is the correct answer.

no but i do not usually comment or use my voice that much when it comes to social media

it is a solid

explanation: