THIS IS A REPOST I WILL STILL GIVE BRAINLIEST FOR ALL ANSWERED QUESTIONS Directions: Identify the manipulated variable and responding variable for each hypothesis.
HINT: If (fill in manipulated variable), then (fill in responding variable)

1. If plants are watered, then growth height will increase.
Manipulated variable:
Responding variable:

2. If chocolate is given to teachers, then amount of homework will decrease.
Manipulated variable:
Responding variable:

3. If trees have leaves, then bird nests will increase.
Manipulated variable:
Responding variable:

4. If acid rain is in water, then fish population will increase.
Manipulated variable:
Responding variable:

5. If calcium is given, then bone strength will increase.
Manipulated variable:
Responding variable:

1. Manipulated: Water

Responding: Growth Height

2. Manipulated: Chocolate Given

Responding: Amount of Homework

3. Manipulated: Trees with Leaves

Responding: Number of Bird Nests

4. Manipulated: Acid Rain

Responding: Fish Population

5. Manipulated: Calcium Given

Responding:  Bone Strength

Think about the manipulated variable as the changing item in the experiment. If this changes, the response will. (This is the Independent Variable)

Think of the Responding Variable as the result of the variable only can change when Manipulated is changed. (This is the Dependent Variable)

Hope This Helps :)

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole