The following reaction shows sodium carbonate reacting with calcium hydroxide. Na2CO3 + Ca(OH)2 → 2NaOH + CaCO3

How many grams of NaOH are produced from 20.0 grams of Na2CO3?

(Molar mass of Na = 22.989 g/mol, C = 12.01 g/mol, O = 15.999 g/mol, Ca = 40.078 g/mol, H = 1.008 g/mol) (5 points)

a. 12.2 grams
b. 15.1 grams
c. 24.4 grams
d. 30.2 grams

15.1 g NaOH

Explanation:

First we convert grams of Na₂CO₃ into moles, using its molar mass:

Molar Mass of Na₂CO₃ = 105.985 g/mol

Then we convert moles of Na₂CO₃ into moles of NaOH, keeping in mind the stoichiometry of the reaction:

Finally we convert NaOH moles into grams, using its molar mass:

Molar Mass of NaOH = 39.996 g/mol

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