What mass of lithium phosphate (Li3PO4) is needed to prepare 500 mL (0.500 L) of a solution having a lithium ion concentration of 0.125 M? a. 2.41 g
b. 6.75 g
c. 10.1 g
d. 19.3 g
e. 30.4 g

a. 2.41 g

Explanation:

First we calculate the number of lithium ion moles (Li⁺) in the solution, multiplying the concentration times the volume:

500 mL ⇒ 500 / 1000 = 0.500 L

Then we convert moles of Li⁺ to moles of Li₃PO₄, keeping in mind that for each mole of Li₃PO₄ there are 3 Li⁺ moles:

Finally we convert Li₃PO₄ moles to grams, using its molar mass:

what is the volume occupied by 40 grams of argon gas (ar) at standard conditions? what volume, in liters, is occupied by 1.5 x 1023 

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