Use the changes in oxidation numbers to determine which elements are oxidized and which are reduced in these reactions. ( note: it is not necessary to use balanced equations. a. C + H2SO4 —->
CO2 + SO2 + H2O
b. HNO3 + HI —-> NO + I2 + H2O
c. KMnO4 + HCl —-> MnCl2 + Cl2 + H2O + KCl
d. Sb + HNO3 —-> Sb2O3 + NO + H2O

Please help me this is due tonight and I can’t figure it out

answer: h+ its less than oh

explanation:

"the periodic table is arranged in order of atomic number."

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o