Calculate the amount of heat, in Joules, needed to raise 34.0g of water from 55.0°C to 76.0*C. The specific heat of water is 4.18 J/gºC.

2984.52J

Explanation:

Using the formula: Q = m × c × ∆T

Where;

Q = amount of heat (in Joules)

m = mass (in grams)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

Based on the information provided in the question;

m = 34.0g

c = 4.18 J/gºC.

Initial temperature = 55.0°C

Final temperature = 76.0°C

Hence, Q = m × c × ∆T

Q = 34 × 4.18 × (76 - 55)

Q = 142.12 × 21

Q = 2984.52J

Therefore, 2984.52J is the amount of heat, in Joules, needed to raise 34.0g of the water.

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explanation:

dasdad

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