Suppose the filament in a super-powerful flashlight is heated up to 3600 k. what type of light would be given off by this filament, mostly?

The correct answer is "Infrared light".

Explanation:

Infrared light, also known as infrared radiation, is a type of light that can no be seen but it can be felt from the heat that it generates. The spectrum of wavelengths that comprise the infrared light is given from 700 nanometers, which is the edge of visible red light, up to 1 millimeter of wavelength. Near-Infrared light is the one that can reach the highest temperature, reaching from 3000 to 5200 K. Therefore, a super-powerful flashlight heated up to 3600 K can be given off infrared light.

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

the objects have the same charge.