Chemistry, 04.12.2020 16:30 southerntouch103

Which pair of orbitals has the same shape? Your

2s and 2p

2s and 1s

3p and 3d

more than one is correct

Answers: 2

Show answers

Answers

Answer from: fffcc7665

The pair "2s and 1s" has the same shape. A complete explanation is below.

Throughout Mendeleev's table, the "s" orbital has a sphere as well as round symmetry. This same wave function would be determined by the difference again from the nucleus rather than the directions.These same 2s, as well as 1s orbitals, are approximately identical in form, with the exception being the 2s orbital appears bigger than the whole 1s orbital.

Thus the above alternative i.e., "option B" is appropriate.

Learn more:

link

Which pair of orbitals has the same shape?

Your
2s and 2p
2s and 1s
3p and 3d
more than one is

Answer from: laylay1548

2s and 1s

Explanation:

The s orbital is spherically symmetrical. The wave function depends on the distance from the nucleus and not on the direction.

The 2s and 1s orbitals are of the same shape only that the 2s orbital is larger than the 1s orbital.

The images of these orbitals are shown in the image attached.

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

Ithink it’s 3 as the answer.

Another question on Chemistry

Chemistry, 21.06.2019 18:30

Asample of the male sex hormone testosterone, c19h28o2, contains 3.88×10^21 atoms of hydrogen.(a) how many atoms of carbon does it contain? (b) how many molecules of testosterone does it contain? (c) how many moles of testosterone does it contain? (d) what is the mass of this sample in grams?

Answers: 1

Answer

Chemistry, 21.06.2019 18:30

Calculate the change in entropy if br2(l) is converted to br2(g). s° for br2(l) = 152.2 j/(mol•k) s° for br2(g) = 245.5 j/(mol•k) s° for br(g) = 175.0 j/(mol•k)

Answers: 3

Answer

Chemistry, 21.06.2019 21:30

Aphysical reaction is a process in which one or more reactants change into one or more products with different properties. select the best answer from the choices provided t f

Answers: 1

Answer

Chemistry, 21.06.2019 22:40

How many electrons does silver have to give up in order to achieve a sido noble gas electron configuration

Answers: 1

Answer

You know the right answer?

Which pair of orbitals has the same shape? Your

2s and 2p

2s and 1s

Questions