If 1.0 volumes of 1.0 M solutions of sodium hydroxide and lead (II) nitrate are mized how many moles of product are produced

0.5 moles of Pb(OH)₂ are produced.

Explanation:    

The reaction is:  

If we have 1.0 liter of 1.0 M of sodium hydroxide and lead (II) nitrate, the number of moles are:  

Now, we need to find the limiting reactant knowing that 2 moles of sodium hydroxide react with 1 mol of lead (II) nitrate:

Since we have 1 mol of sodium hydroxide and we need 2 moles to react with lead (II) nitrate, then the limiting reactant is sodium hydroxide.

We can find the number of moles of lead (II) hydroxide produced as follows:

Therefore, 0.5 moles of Pb(OH)₂ are produced.

I hope it helps you!  

explanation:

two years ago, when picking flowers in the mountains back of yosemite valley, i found a book. it was blotted and storm-beaten; all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however; many of the inner pages were well preserved. and although all were more or less stained and torn, whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today; its granite pages have been torn and blurred by the same storms that wasted the castaway book.

two years ago, when picking flowers in the mountains back of yosemite valley; i found a book. it was blotted and storm-beaten, all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however, many of the inner pages were well preserved. and although all were more or less stained and torn; whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today, its granite pages have been torn and blurred by the same storms that wasted the castaway book.