If 10.28 g of Cu(NO3)2 are obtained from the reaction of 4.54 g of Cu with excess HNO3, what is the percent yield of the reaction? (show workings for full grade)

The percent yield of the reaction : 77.2%

Percent yield is the comparison of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

Reaction

Cu + 4HNO₃ → Cu(NO₃)₂ + 2NO₂ + 2H₂O

mol of Cu(MW=63.55 g/mol) :

mol ratio Cu : Cu(NO₃)₂ = 1 : 1, so mol Cu(NO₃)₂ :

mass of Cu(NO₃)₂ (MW=187,56 g/mol) :

10.28 g of Cu(NO₃)₂ are obtained from the reaction⇒actual yield

The percent yield :

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation: