If 85 g of NH4Cl reacts with 130 g of Ca(OH)2 according to the following reaction, what is the maximum mass of ammonia that can be formed? 2 NH4Cl + Ca(OH)2 CaCl2 + 2 NH3 + 2 H2O

pay attenion and you would be able to figure it out dont

cheat

Explanation:

c. 75.7

i think that is the right

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.