Ammonia NH3 gas and oxygen O2 gas react to form nitrogen N2 gas and water H2O vapor. Suppose you have 2.0 mol of NH3 and 13.0 mol of O2 in a reactor. Calculate the largest amount of N2 that could be produced. Round your answer to the nearest 0.1 mol.

1.0 mol N₂

Explanation:

The reaction that takes place is:

First we determine the limiting reactant:

13.0 mol of O₂ would react completely with (13*4/3) 17.3 moles of NH₃. There are not as many NH₃ moles so NH₃ is the limiting reactant.

Then we calculate the number of N₂ that could be formed from the given moles of NH₃:

2.0 mol NH₃ * =  1.0 mol N₂

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6