A chemist prepares a solution of calcium bromide by weighing out 0.607g of calcium bromide into a 450ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in of the chemist's calcium bromide solution. Be sure your answer has the correct number of significant digits.

0.00676 M

Explanation:

A chemist prepares a solution of calcium bromide by weighing out 0.607g of calcium bromide into a 450ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's calcium bromide solution. Be sure your answer has the correct number of significant digits.

Step 1: Given data

Mass of calcium bromide (solute): 0.607 g

Volume of solution: 450 mL

Step 2: Calculate the moles corresponding to 0.607 g of calcium bromide

The molar mass of CaBr₂ is 199.89 g/mol.

0.607 g × 1 mol/199.89 g = 0.00304 mol

Step 3: Convert the volume of solution to liters

We will use the conversion factor 1 L = 1000 mL.

450 mL × 1 L/1000 mL = 0.450 L

Step 4: Calculate the molar concentration of calcium bromide

The molarity of the solution is:

M = moles of solute / liters of solution

M = 0.00304 mol / 0.450 L

M = 0.00676 M

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer