A mixture of9 mol Fz and 4 mol S are allowed to react. 3Fz+ S---+ SF6 How many moles ofFz remain after 3 mol ofS have reacted?

0 moles of F2

Explanation:

The equation of the reaction is given as;

3F2 + S ---> SF6

From the reaction above;

3 moles of F2 requires 1 mol of S to form 1 mole of SF6

How many moles of F2 would then require 3 mol of S ?

3 = 1

x = 3

x = 3 * 3 / 1 = 9 / 1 = 9 moles of F2

There would be no moles of F2 left as everything would be used up in the reaction.

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.