Select all the correct answers. In this reaction, how does the rate of forward reaction vary with the concentration of the product?
2H, S() =2H() + S(g)
O It increases with an increase in the concentration of S-(g).
OIt decreases with a decrease in the concentration of H().
OIt increases with a decrease in the concentration of H-(g).
It decreases with an increase in the concentration of S,().
It decreases with increase in the concentration of Ha().

The correct answers :

It increases with a decrease in the concentration of H₂(g).

It decreases with an increase in the concentration of S₂(g).

It decreases with an increase in the concentration of H₂(g).

Forward reaction : rate to form product

In equilibrium :

The product decreases ⇒ system will move from left to right(forward reaction)

The product increases ⇒ system will move from right to left(reverse reaction)

no

explanation:

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explanation: