Calculate the maximum volume in mL of 0.20 M HCl that a tablet containing 338 mg Al(OH)3 and 489 mg Mg(OH)2 would be expected to neutralize. Assume complete neutralization.

148.85 mL

Explanation:

The reactions that take place are:

Now we calculate how many HCl moles would react with 338 mg of Al(OH)₃. First we convert Al(OH)₃ mg into mmol, using its molar mass:

Then we convert mmol Al(OH)₃ into mmol HCl:

Now we do the same calculations for Mg(OH)₂, using its molar mass:

And convert into mmol HCl:

Now we add the reacting mmoles of HCl together

Finally we calculate the volume of a 0.20 M solution that contains 29.77 mmoles of HCl:

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