If you exposed a plant to C14O218, and flashed a light on it for a short period, in which products would you expect to see the label in a few minutes?a. the C14 would be in Glyceraldehyde 3-Phosphate, and the O18 would be molecular Oxygenb. The C14 would be released as CO2, and the O18 would appear in H2Oc. The C14 would be found in Glyceraldehyde-3-Phosphate, and the O18 would also be found in the same molecule. d. The C14would appear in Ribulose bis Phosphate, and the O18 would be released as molecular Oxygene. None of the above

The C14 would be found in Glyceraldehyde-3-Phosphate, and the O18 would also be found in the same molecule

Explanation:

Isotopic labeling is a common method for deducing reaction mechanism in chemistry.

In photosynthesis, the oxygen in the found in Glyceraldehyde-3-Phosphate comes from the carbon dioxide, This is also finally found in the glucose produced at the end of the cycle.

The oxygen in water is released into the atmosphere as the oxygen molecule.

Therefore, the C14 would be found in Glyceraldehyde-3-Phosphate, and the O18 would also be found in the same molecule.

a saline water is fed to a reverse osmosis unit at flow rate o rotameter connected to reject (retentate) line reads 8 installed in reject and permeate line reads 15.2 milli siemens/cm and 300 micro siemens/com respectively.

the formula mass of a molecule or a compound is the sum of the atomic weights of the atoms in its empirical formula

(that's what i know about formula mass)