How much energy is required to change 110 grams of steam at 181 C to 40 C

Q = -64893.84 J

Explanation:

Given data:

Mass of steam = 110 g

Initial temperature = 181 °C

Final temperature = 40°C

Energy released = ?

Solution:

Energy will released in this process because temperature is going to be decreased.

Specific heat capacity of water is 4.184 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 40°C - 181 °C

ΔT = -141°C

Q =  110 g × 4.184 J/g.°C × -141°C

Q = -64893.84 J

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