Please help. D) 250 ml KOH solution 30% mass
grams of KOH = 101.25
grams of water = 236.25

Obtain:
-mass solution = ?
-mass solute = ?
-solvent mass = ?

msolution= solute mass + solvent mass

Mass= (mass of solution)*100

i believe you are right for all except the 3rd ( look at sqdancefan his answer is much better)

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation:

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.