How many moles of C2H6 are needed to completely react with 4.30 moles of O2 according to the above equation? a
1.25 moles of CH4

b
205 moles of CH4

c
0.798 moles of CH4

d
0.036 moles of CH4

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

c. orbital shape i hope this is correct