How many moles of Ba(NO3)2 are there in 0.25 L of a 2.00 M Ba(NO3)2 solution? Use Molarity equals StartFraction moles of solute over liters of solution EndFraction..
0.13 mol
0.50 mol
2.25 mol
8.0 mol

0.5moles

Explanation:

Given parameters:

Volume of solution= 0.25L

Molarity of solution = 2.00M

Unknown:

Number of moles  = ?

Solution:

To solve this problem;

  Molarity is the number of moles of solute in a given volume of solution, so

 Number of moles  = molarity x volume

 Now insert the parameters and solve;

  Number of moles  = 0.25 x 2  = 0.5moles

the increase of protons   hope this

it means there are 3 atoms of oxygen