a solution of AICI is combined with a solution of KOH. Identify the precipitate and the spectator ions in the resulting reactions.

The  the precipitate : Al(OH)₃(s)

The spectator ions : 3Cl⁻ and 3K⁺

Reaction

AlCl₃ + 3KOH → Al(OH)₃ + 3KCl

From solubility rules :

Compounds of OH− are insoluble except Compounds of Li +, Na +, K +, Rb +, Cs +, NH₄⁺ , Sr²⁺, and Ba²⁺

Compounds of Cl−, Br−, I− are soluble except Ag⁺, Hg₂²⁺, Pb²⁺

So the  the precipitate : Al(OH)₃(s)

net ionic reaction

AlCl₃ + 3KOH → Al(OH)₃ + 3KCl

Al³⁻+3Cl⁻+3K⁺+3OH⁻⇒Al(OH)₃(s)+3K⁺+3Cl⁻

Remove the spectator : 3Cl⁻ and 3K⁺

Al³⁻(aq)+3OH⁻(aq)⇒Al(OH)₃(s)

hey your not cool]      

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.