1. Define the units for molarity. Page |152 Exp. 14 pH and Solutions Pre Lab Questions (1 of 1) 2. A solution contains 5.25 grams of sodium chloride in 750.0 mL of solution. Determine the molarity of the solution. Na

1. mol/L

2. 0.120 M

Explanation:

1. Molarity is equal to the moles of solute divided by the liters of solution. The units of molarity are mol/L.

2.

Step 1: Given data

Step 2: Calculate the moles of solute (n)

The molar mass of NaCl is 58.44 g/mol.

n = 5.25 g × 1 mol/58.44 g = 0.0898 mol

Step 3: Determine the molarity of the solution

We will use the definition of molarity

M = n/V

M = 0.0898 mol / 0.7500 L = 0.120 M

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).