How would you prepare 175.0ml of 0.150m agno3 solution starting with pure solute?

Therefore, we need to dissolve 4.5 g of [tx]AgNO_3[/tex] and make the volume upto 175 ml.

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution

where,

n= moles of solute  

= volume of solution in ml = 175.0 ml

Now put all the given values in the formula of molarity, we get

Therefore, we need to dissolve 4.5 g of [tx]AgNO_3[/tex] and make the volume upto 175 ml.

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b