Determine the mass of antimony produced when 1.50 grams of antimony(III) oxide reacts. g Sb
Sb2O3(s) + 3 C(s) --> 2 Sb(s) + 3 CO(g)
**Report your answer to the correct number of significant digits!

Mass = 1.217 g

Explanation:

Given data:

Mass of Sb₂O₃ = 1.50 g

Mass of Sb produced = ?

Solution:

Chemical equation:

Sb₂O₃ + 3C    →     2Sb + 3CO

Number of moles of Sb₂O₃:

Number of moles = mass/ molar mass

Number of moles = 1.50 g/ 291.49 g/mol

Number of moles = 0.005 mol

now we will compare the moles of Sb₂O₃ and Sb.

                   Sb₂O₃          :           Sb

                      1                :           2

                     0.005        :       2/1×0.005 = 0.01

Mass of Sb:

Mass = number of moles × molar mass

Mass = 0.01 mol × 121.76 g/mol

Mass = 1.217 g

your answer would be “dry”