How much water would you need to add to 500 mL of a 2.4 M KCl solution to make a 1.0 M solution?

Use dilution equation:  

M1V1 = M2V2  

1.0*V1 = 2.4*500  

V1 = 1200mL  

You already have 500mL KCl solution . You must add: 1200mL - 500mL = 700mL water.

Explanation:

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the answer is:  

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answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;