How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 34.5 grams of sodium hydroxide in the single replacement reaction below? Unbalanced equation: Na + H2O ---> NaOH + H2

Volume of Sodium metal : 20.454 ml

Further explanation

Reaction(balanced) :

2Na + 2H₂O → 2NaOH + H₂

mass NaOH = 34.5 g

mol NaOH(MW=40 g/mol) :

From the equation, mol ratio of Na : NaOH = 2 : 2, so mol Na=mol NaOH=0.8625

Mass Na (Ar=23 g/mol):

Volume Na :

Molarity is moles of solute over liters of solution. idk if that is what you are talking about, but you can convert moles of solute to grams of solute using dimensional analyzes by using molar mass found on the periodic table.

Ithink the answer is 10.576