On a cold winter morning when the temperature is -13 C, the air pressure in an automobile is 1.5 atm. Using Gay Lussac's Law, what is the pressure after the tire has warmed to 15 degrees C?

The correct answer is 1.66 atm ≅ 1.7 atm

Explanation:

Given:

T₁ = -13°C + 273 = 260 K (initial temperature)

T₂ = 15°C + 273 = 288 K (final temperature)

P₁ = 1.5 atm

P₂= ?

We use the mathematical expression of Gay Lussac's Law to calculate P₂, as follows:

P₁/T₁ = P₂/T₂

P₂= P₁/T₁ x T₂ = (1.5 atm)/(260 K) x 288 K = 1.66 atm ≅ 1.7 atm

Since the law says that the temperature of a gas is directly proportional to the pressure, when the temperature is increased, the pressure increases.

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