In this reaction, how does the rate of forward reaction vary with the concentration of the product? 2H2S(g) ⇌ 2H2(g) + S2(g)

It increases with an increase in the concentration of S2(g).

It decreases with a decrease in the concentration of H2(g).

It increases with a decrease in the concentration of H2(g).

It decreases with an increase in the concentration of S2(g).

It decreases with increase in the concentration of H2(g).

(Multiple answers)

the role of the microscope world in creating new materials .

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

i believe the answer is true.