A student mixes 50.0 mL of 1.00 M Ba(OH)2 with 83.5 mL of 0.475 M H2SO4. Calculate the mass of BaSO4 formed.

9.26g of BaSO₄ are formed

Explanation:

The reaction of Ba(OH)₂ with H₂SO₄ is:

Ba(OH)₂ + H₂SO₄ → BaSO₄ + 2H₂O.

To solve this question we need to determine the moles of each reactant in order to find the limitng reactant. With the moles of limiting reactant we can find the theoretical moles of BaSO₄ produced and its mass, as follows:

Moles Ba(OH)₂:

50.0mL = 0.050L * (1.00mol / L) = 0.0500moles

Moles H₂SO₄:

83.5mL = 0.0835L * (0.475mol / L) = 0.0397moles

That means limiting reactant is H₂SO₄.

Based on the reaction, 1 mole of H₂SO₄ produce 1 mole of BaSO₄. The theoretical moles of BaSO₄ produced are 0.0397 moles.

The mass is (Molar mass BaSO₄: 233.38g/mol):

0.0397 moles BaSO₄ * (233.38g / mol) =

1 a

2 d

3 a

4 c

explanation:

definition

                    entropy is a measure of the randomness or the extent of disorder of a chemical process.

                      enthalpy is a measure of the heat change of a reaction occurring at a constant pressure.

measurement units:

                        entropy is measured in joule per kelvin (jk⁻¹)   whereas enthalpy is measured in joule per mole (jmol⁻¹)

requirements:

                            entropy has no requirements or limits, and its change is measured by the division between the heat change of the chemical process and the temperature.

                              in contrast, enthalpy can only be related to the heat change of the reaction under standard conditions.